求eva手机壳原图清晰原图(家徽+英文+底图)

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家徽的英文
英文翻译heraldrymon:&&&& household:&&&& insignia
例句与用法1.The birth came about an hour after kiko 39 was reported to have undergone a caesarean 3 section指日本皇朝,其家徽为菊纹。 “ chrysanthemum ”是“菊花”的意思。 2.The girls wore the " furisode , " a long - sleeved kimono , while guys wore the " montsuki hakama " a men s formal crested kimono and a " hakama " skirt的协助下试穿和服。女生试穿的是长袖和服,男生试穿的是印有家徽的非常正式的和服。 3.It was called the d urberville window , and in the upper part could be discerned heraldic emblems like those on durbeyfield s old seal and spoon那个窗户也被称为德北菲尔德窗户在窗户的上半部分可以看到家徽一样的装饰,同德北菲尔德家保存的古印和汤匙上的装饰一模一样。 4.Arranged successively in ascending powers of hierarchical order , that of gardener , groundsman , cultivator , breeder , and at the zenith of his career , resident magistrate or justice of the peace with a family crest and coat of arms and appropriate classical motto semper paratus , duly recorded in the court directory bloom , leopold p . , m . p . , p . c . , k . p . , l . l . d . honoris cause , bloomville , dundrum and mentioned in court and fashionable intelligence mr and mrs leopold bloom have left kingstown for england按照越往上权利越大的等级制度顺序,他曾经是园丁庄稼人耕作者牲畜繁殖家仕途的高峰是地方长官或治安推事。他拥有家徽和盾形纹章以及与之相称的拉丁文家训时刻准备着,他的名字正式记载于宫廷人名录252中布卢姆,利奥波德保,下院议员,枢密顾问官,圣巴特里克勋级爵士253 ,名誉法学博士。
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家徽的英文翻译,家徽英文怎么说,怎么用英语翻译家徽,家徽的英文意思,发音,例句,用法和解释由查查在线词典提供,版权所有违者必究。请阅读下列材料:问题:如图(1),一圆柱的底面半径、高均为5cm,BC是底面直径,求一只蚂蚁从A点出发沿圆柱表面爬行到点C的最短路线.小明设计了两条路线:路线1:侧面展开图中的线段AC.如下图(2)所示:设路线1的长度为l1,则l12=AC2=AB2+$\widehat{BC}$2=52+(5π)2=25+25π2路线2:高线AB+底面直径BC.如上图(1)所示:设路线2的长度为l2,则l22=(AB+BC)2=(5+10)2=225l12-l22=25+25π2-225=25π2-200=25(π2-8)>0∴l12>l22∴l1>l2所以要选择路线2较短.(1)小明对上述结论有些疑惑,于是他把条件改成:“圆柱的底面半径为1cm,高AB为5cm”继续按前面的路线进行计算.请你帮小明完成下面的计算:路线1:l12=AC2=25+π2;路线2:l22=(AB+BC)2=49∵l12<l22∴l1<l2(填>或<)∴选择路线1(填1或2)较短.(2)请你帮小明继续研究:在一般情况下,当圆柱的底面半径为r,高为h时,应如何选择上面的两条路线才能使蚂蚁从点A出发沿圆柱表面爬行到C点的路线最短.
(1)根据勾股定理易得路线1?∈l12=AC2=高2+底面周长一半2;路线2:l22=(高+底面直径)2;让两个平方比较,平方大的,底数就大.(2)根据(1)得到的结论让两个代数式分三种情况进行比较即可.(1)路线1:l12=AC2=25+π2;路线2:l22=(AB+BC)2=49.∵l12<l22,∴l1<l2(填>或<),∴选择路线1(填1或2)较短.(5分)(2)l12=AC2=AB2+$\widehat{BC}$2=h2+(πr)2,l22=(AB+BC)2=(h+2r)2,l12-l22=h2+(πr)2-(h+2r)2=r(π2r-4r-4h)=r[(π2-4)r-4h];r恒大于0,只需看后面的式子即可.(2分)当$r=\frac{4h}{{{π^2}-4}}$时,l12=l22;当r>$\frac{4h}{{{π^2}-4}}$时,l12>l22;当r<$\frac{4h}{{{π^2}-4}}$时,l12<l22.

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