如题2,求解

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如题23图,反比例函数(,)的图象与直线相交于点C,过直线上点A(1,3)作 AB⊥x轴于点B,交反比例函数图象于点D,且AB=3BD. (1)
求k的值; (2)
求点C的坐标; (3)
在y轴上确实一点M,使点M到C、D两点距离之和d=MC+MD,求点M的坐标.
五、解答题(三)
23.&& 如题23图,反比例函数(,)的图象与直线相交于点C,过直线上点A(1,3)作 AB&x轴于点B,交反比例函数图象于点D,且AB=3BD.
(1)&& 求k的值;
(2)&& 求点C的坐标;
(3)&& 在y轴上确实一点M,使点M到C、D两点距离之和d=MC+MD,求点M的坐标.
【解析】(1)&& ∵A(1,3),
∴OB=1,AB=3,
又AB=3BD,
∴BD=1,
∴B(1,1),
∴;
(2)&& 由(1)知反比例函数的解析式为,
解方程组,得或(舍去),
∴点C的坐标为(,);
(3)&& 如图,作点D关于y轴对称点E,则E(,1),连接CE交y轴于点M,即为所求.
设直线CE的解析式为,则
,解得,,
∴直线CE的解析式为,
当x=0时,y=,
∴点M的坐标为(0,).
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